Optimal. Leaf size=118 \[ \frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac {5 d-8 e x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {15 d-16 e x}{15 d^5 \sqrt {d^2-e^2 x^2}}-\frac {\tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )}{d^5} \]
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Rubi [A]
time = 0.11, antiderivative size = 118, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 7, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.259, Rules used = {866, 1819, 837,
12, 272, 65, 214} \begin {gather*} \frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac {15 d-16 e x}{15 d^5 \sqrt {d^2-e^2 x^2}}-\frac {\tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )}{d^5}+\frac {5 d-8 e x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 65
Rule 214
Rule 272
Rule 837
Rule 866
Rule 1819
Rubi steps
\begin {align*} \int \frac {1}{x (d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx &=\int \frac {(d-e x)^2}{x \left (d^2-e^2 x^2\right )^{7/2}} \, dx\\ &=\frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}-\frac {\int \frac {-5 d^2+8 d e x}{x \left (d^2-e^2 x^2\right )^{5/2}} \, dx}{5 d^2}\\ &=\frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac {5 d-8 e x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}-\frac {\int \frac {-15 d^4 e^2+16 d^3 e^3 x}{x \left (d^2-e^2 x^2\right )^{3/2}} \, dx}{15 d^6 e^2}\\ &=\frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac {5 d-8 e x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {15 d-16 e x}{15 d^5 \sqrt {d^2-e^2 x^2}}-\frac {\int -\frac {15 d^6 e^4}{x \sqrt {d^2-e^2 x^2}} \, dx}{15 d^{10} e^4}\\ &=\frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac {5 d-8 e x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {15 d-16 e x}{15 d^5 \sqrt {d^2-e^2 x^2}}+\frac {\int \frac {1}{x \sqrt {d^2-e^2 x^2}} \, dx}{d^4}\\ &=\frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac {5 d-8 e x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {15 d-16 e x}{15 d^5 \sqrt {d^2-e^2 x^2}}+\frac {\text {Subst}\left (\int \frac {1}{x \sqrt {d^2-e^2 x}} \, dx,x,x^2\right )}{2 d^4}\\ &=\frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac {5 d-8 e x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {15 d-16 e x}{15 d^5 \sqrt {d^2-e^2 x^2}}-\frac {\text {Subst}\left (\int \frac {1}{\frac {d^2}{e^2}-\frac {x^2}{e^2}} \, dx,x,\sqrt {d^2-e^2 x^2}\right )}{d^4 e^2}\\ &=\frac {2 (d-e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac {5 d-8 e x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {15 d-16 e x}{15 d^5 \sqrt {d^2-e^2 x^2}}-\frac {\tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )}{d^5}\\ \end {align*}
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Mathematica [A]
time = 0.47, size = 107, normalized size = 0.91 \begin {gather*} \frac {\frac {\sqrt {d^2-e^2 x^2} \left (26 d^3+22 d^2 e x-17 d e^2 x^2-16 e^3 x^3\right )}{(d-e x) (d+e x)^3}+30 \tanh ^{-1}\left (\frac {\sqrt {-e^2} x-\sqrt {d^2-e^2 x^2}}{d}\right )}{15 d^5} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(329\) vs.
\(2(104)=208\).
time = 0.07, size = 330, normalized size = 2.80
method | result | size |
default | \(-\frac {-\frac {1}{3 d e \left (x +\frac {d}{e}\right ) \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}-\frac {-2 e^{2} \left (x +\frac {d}{e}\right )+2 d e}{3 e \,d^{3} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}}{d^{2}}-\frac {-\frac {1}{5 d e \left (x +\frac {d}{e}\right )^{2} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}+\frac {3 e \left (-\frac {1}{3 d e \left (x +\frac {d}{e}\right ) \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}-\frac {-2 e^{2} \left (x +\frac {d}{e}\right )+2 d e}{3 e \,d^{3} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{5 d}}{e d}+\frac {\frac {1}{d^{2} \sqrt {-e^{2} x^{2}+d^{2}}}-\frac {\ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{d^{2} \sqrt {d^{2}}}}{d^{2}}\) | \(330\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 2.78, size = 162, normalized size = 1.37 \begin {gather*} \frac {26 \, x^{4} e^{4} + 52 \, d x^{3} e^{3} - 52 \, d^{3} x e - 26 \, d^{4} + 15 \, {\left (x^{4} e^{4} + 2 \, d x^{3} e^{3} - 2 \, d^{3} x e - d^{4}\right )} \log \left (-\frac {d - \sqrt {-x^{2} e^{2} + d^{2}}}{x}\right ) + {\left (16 \, x^{3} e^{3} + 17 \, d x^{2} e^{2} - 22 \, d^{2} x e - 26 \, d^{3}\right )} \sqrt {-x^{2} e^{2} + d^{2}}}{15 \, {\left (d^{5} x^{4} e^{4} + 2 \, d^{6} x^{3} e^{3} - 2 \, d^{8} x e - d^{9}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x \left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac {3}{2}} \left (d + e x\right )^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [C] Result contains complex when optimal does not.
time = 1.39, size = 254, normalized size = 2.15 \begin {gather*} -\frac {1}{120} \, {\left (\frac {120 \, e^{\left (-4\right )} \log \left (\sqrt {\frac {2 \, d}{x e + d} - 1} + 1\right )}{d^{5} \mathrm {sgn}\left (\frac {1}{x e + d}\right )} - \frac {120 \, e^{\left (-4\right )} \log \left ({\left | \sqrt {\frac {2 \, d}{x e + d} - 1} - 1 \right |}\right )}{d^{5} \mathrm {sgn}\left (\frac {1}{x e + d}\right )} - \frac {15 \, e^{\left (-4\right )}}{d^{5} \sqrt {\frac {2 \, d}{x e + d} - 1} \mathrm {sgn}\left (\frac {1}{x e + d}\right )} - \frac {{\left (3 \, d^{20} {\left (\frac {2 \, d}{x e + d} - 1\right )}^{\frac {5}{2}} e^{16} \mathrm {sgn}\left (\frac {1}{x e + d}\right )^{4} + 25 \, d^{20} {\left (\frac {2 \, d}{x e + d} - 1\right )}^{\frac {3}{2}} e^{16} \mathrm {sgn}\left (\frac {1}{x e + d}\right )^{4} + 165 \, d^{20} \sqrt {\frac {2 \, d}{x e + d} - 1} e^{16} \mathrm {sgn}\left (\frac {1}{x e + d}\right )^{4}\right )} e^{\left (-20\right )}}{d^{25} \mathrm {sgn}\left (\frac {1}{x e + d}\right )^{5}}\right )} e^{4} - \frac {{\left (15 \, \log \left (2\right ) - 30 \, \log \left (i + 1\right ) + 32 i\right )} \mathrm {sgn}\left (\frac {1}{x e + d}\right )}{30 \, d^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{x\,{\left (d^2-e^2\,x^2\right )}^{3/2}\,{\left (d+e\,x\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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